This time I will give java post interesting lessons
so check this out ..
convert decimal numbers with java --->
step one, please look coding above
use application the name is Net beans
chect this out....
use application the name is Net beans
chect this out....
package Praktek1;
import java.util.Scanner;
import javax.swing.JOptionPane;
public class latihan_konvers {
//global variable
static String name;//object
static String kelamin;
static int bilDes;//variable
//fingsi/method rekursi
public static void Biner(int n){
if(n>1) {Biner(n/2);}
System.out.print(n%2);
}
public static void Hexa(int n){
char[] daftarHexa={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
int sisaBagi = n%16;
if(n>0){
Hexa((n - sisaBagi) / 16);
}
System.out.print(daftarHexa[n%16]);
}
public static void Oktal(int n){
char[] daftarOktal={'0','1','2','3','4','5','6','7'};
int sisaBagi = n %8;
if(n>0){
Oktal((n - sisaBagi) / 8);
System.out.print(daftarOktal[n%8]);
}
}
public static void inputDes(){
System.out.print("Masukkan Bilangan Desimal= ");
Scanner inputan=new Scanner(System.in);
bilDes=inputan.nextInt();
//return bilDes
}
public static void tampilBiner(){
inputDes();
System.out.print("Binernya adalah ");
Biner(bilDes);
}
public static void tampilHexa(){
inputDes();
System.out.print("Hexanya Adalah ");
Hexa(bilDes);
}
public static void tampilOktal(){
inputDes();
System.out.print("Oktalnya adalah ");
Oktal(bilDes);
}
public static int inpBil (){
System.out.println("=========================================="
+ "\nSelamat datang "+kelamin+" "+name+"");
System.out.println("Silahkan memilih menu konversi "
+ "Bilangan ke: "+
"\n1. Biner \n2. Hexa \n3. Oktal \n4. Exit");
System.out.print("Masukkan Angka Menu= ");
Scanner inputan=new Scanner(System.in);
int pilmenu=inputan.nextInt();
return pilmenu;
}
public static void menU(int pil){
System.out.println("\033");//clear screen
switch(pil){
case 1: tampilBiner(); break;
case 2: tampilHexa(); break;
case 3: tampilOktal(); break;
case 4: System.out.println("Kamsia ya, sudah mampir.");
System.exit(0); break;//memberikan kondisi FALSE
default:System.out.println("(Maaf. Pilih angka 1-4 saja!)");
break;
}
System.out.println("\033");//clear screen
}
public static void main(String arg[]){
name=JOptionPane.showInputDialog("Masukkan nama Anda : ");//menampilkan input dialog untuk memasukkan nama
//menampilkan Option Dialog untuk memilih jenis kelamin
String[] choices = {"Perempuan", "Laki-Laki", "WARIA"};
String Perempuan= "Mbak";
String Laki= "Mas";
while (true) {
int response = JOptionPane.showOptionDialog(
null
, "Apa jenis kelamin Anda ?"
, "Jenis Kelamin"
, JOptionPane.YES_NO_OPTION
, JOptionPane.QUESTION_MESSAGE
, null
, choices
, "Quit"
);
switch(response){
case 0 : kelamin = Perempuan;
break;
case 1 : kelamin = Laki;
break;
case 2:
System.out.println("maaf gak bisa kalo gak laki laki atau perempuan,silahkan melakukan penetapan kelamin!! ");
System.exit(0); break;
}
do{
menU(inpBil());
}
while(true);
}
}
}
click shift+f6. then...
enter your name
choose your gender , for example, "Laki-laki"
If you click on one of the man will appear :
Example write the numbers 1, as shown :
Then insert the decimal number :
and will see the results of binary
To exit, content with the number 4:
and finish ..
That was my post, maybe useful if there is a lack of forgiveness.
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